Z Table



Study about standard normal distribution.

Normal distribution


$$ \large f(x|\mu, \sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}=\frac{1}{\sigma\sqrt{2\pi}}e^{-\frac{1}{2}\left(\frac{x-\mu}{\sigma}\right)^2} $$

where,

Standard normal distribution


Special case of density probability, when $\mu=0$ and $\sigma=1$ $$ \large f(x)=\frac{1}{\sqrt{2\pi}}e^{-\frac{1}{2}x^2} $$

Cumulative distribution function


$$ \large \Phi(z)=\frac{1}{2\pi}\int_{-\infty}^{z}e^{-\frac{t^2}{2}}dx $$

For the range $[-\infty, \infty]$ the value of $\Phi$ should be $1$.

Cumulative from mean


$$ \large f(z)=\frac{1}{2\pi}\int_{0}^{z}e^{-\frac{t^2}{2}}dx $$

Probability from 0 to Z, or: $$ \large f(z)=\Phi(z) - \frac{1}{2} $$

Z-Score


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